My question is "Why this theorem is important? Well here is one answer: The study of the Gauss-Kuzmin problem eventually led to a fruitful connection between continued fractions and functional analysis. Namely, the distribution function of the Gauss measure is the leading eigenfunction for the transfer operator associated to the Gauss transformation. It turns out that this is the hidden explanation for the theorem you quoted in your question.
Understanding this connection recently led to a detailed study of transfer operators of the Gauss map and related transformations, and their associated Dirichlet series, which paved the way for major breakthroughs by Baladi, Vallee, and others, in understanding the statistics of the Euclidean algorithm and its various analogues. It would be difficult to give more details than this without writing a very long post, but if you are interested in finding out more then here are two references:.
If you can solve some problem using continued fraction then via Gauss-Kuz'min statistics you can study this problem from statistical point of view. The length of "neaest integer" continued fraction and "odd" continued fractions can be expressed in terms of Gauss-Kuz'min statistics for classical continued fractions.
Corrolary: formula for the average length of such fractions and corresponding Euclidean algorithms. Lattice reduction. Gauss-Kuz'min statistics give you average distribution of 2-dimensional rediced bases. The simplest way to find Frobenius number with three arguments is to use Rodseth's formula. It expresses Frobenius number in terms of some continued fraction. Gauss-Kuz'min statistics give you average behaviour of Frobenius numbers.
Why do we need Gauss-Kuz'min statistics?
Sign up to join this community. The best answers are voted up and rise to the top. Home Questions Tags Users Unanswered. Gauss-Kuzmin Theorem continued fractions - why is important? Ask Question. Asked 8 years, 10 months ago. Active 6 years, 9 months ago. Viewed 1k times. Thank you! Dan L Dan L 81 2 2 bronze badges. If you care about understanding patterns in continued fraction expansions then this theorem is important to you; if you don't care then forget about it. Interesting in what sense?
Active Oldest Votes.In mathematicsthe Gauss—Kuzmin—Wirsing operator is the transfer operator of the Gauss map. It occurs in the study of continued fractions ; it is also related to the Riemann zeta function. It is hard to approximate it by a single smooth polynomial. The first eigenfunction of this operator is.
This eigenfunction gives the probability of the occurrence of a given integer in a continued fraction expansion, and is known as the Gauss—Kuzmin distribution. This follows in part because the Gauss map acts as a truncating shift operator for the continued fractions : if.
Analytic forms for additional eigenfunctions are not known. It is not known if the eigenvalues are irrational. Let us arrange the eigenvalues of the Gauss—Kuzmin—Wirsing operator according to an absolute value:.
InGiedrius Alkauskas proved this conjecture.
The eigenvalues form a discrete spectrum, when the operator is limited to act on functions on the unit interval of the real number line. The series. A special case arises when one wishes to consider the Haar measure of the shift operator, that is, a function that is invariant under shifts.
This is given by the Minkowski measure? That is, one has that G? The GKW operator is related to the Riemann zeta function. Note that the zeta function can be written as. That is, let. Then the GKW operator acts on the Taylor coefficients as. This operator is extremely well formed, and thus very numerically tractable.
The Gauss—Kuzmin constant is easily computed to high precision by numerically diagonalizing the upper-left n by n portion. There is no known closed-form expression that diagonalizes this operator; that is, there are no closed-form expressions known for the eigenvectors.
By writing. The values get small quickly but are oscillatory.
Some explicit sums on these values can be performed. They can be explicitly related to the Stieltjes constants by re-expressing the falling factorial as a polynomial with Stirling number coefficients, and then solving. More generally, the Riemann zeta can be re-expressed as an expansion in terms of Sheffer sequences of polynomials. This expansion of the Riemann zeta is investigated in the following references. From Wikipedia, the free encyclopedia.
Structure of the eigenvalues and trace formulas". USSR Comput. And Math. International Journal of Mathematics and Mathematical Sciences. Journal of Computational and Applied Mathematics.
So some experiments can give this function. The baseline was that nobody knows. Apparently gauss wrote in a letter that "an easy calculation shows that For the rest of the talk he presented some approaches that Gauss might have taken. But in the end we don't know. Sign up to join this community. The best answers are voted up and rise to the top. Home Questions Tags Users Unanswered. How did Gauss discover the invariant density for the Gauss map? Ask Question. Asked 10 years, 5 months ago.
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I should also mention that this question's subject area seems relevant to the topic of dynamical zeta functionsthough I don't know any details. Therefore we have. Therefore we obtain the coefficients. Sign up to join this community. The best answers are voted up and rise to the top. Home Questions Tags Users Unanswered. A question about continued fractions and Gauss map Ask Question.
It was one of the first analytic continued fractions known to mathematics, and it can be used to represent several important elementary functionsas well as some of the more complicated transcendental functions. Lambert published several examples of continued fractions in this form inand both Euler and Lagrange investigated similar constructions,  but it was Carl Friedrich Gauss who utilized the algebra described in the next section to deduce the general form of this continued fraction, in Although Gauss gave the form of this continued fraction, he did not give a proof of its convergence properties.
Bernhard Riemann  and L. These identities can be proven in several ways, for example by expanding out the series and comparing coefficients, or by taking the derivative in several ways and eliminating it from the equations generated. This expansion converges to the meromorphic function defined by the ratio of the two convergent series provided, of course, that a is neither zero nor a negative integer.
In this section, the cases where one or more of the parameters is a negative integer are excluded, since in these cases either the hypergeometric series are undefined or that they are polynomials so the continued fraction terminates. Other trivial exceptions are excluded as well. The continued fractions on the right hand side will converge uniformly on any closed and bounded set that contains no poles of this function.
The continued fractions on the right hand side will converge to the function everywhere inside this circle. The continued fraction converges to a meromorphic function on this domain, and it converges uniformly on any closed and bounded subset of this domain that does not contain any poles. This particular expansion is known as Lambert's continued fraction and dates back to The expansion of tanh can be used to prove that e n is irrational for every integer n which is alas not enough to prove that e is transcendental.
With some manipulation, this can be used to prove the simple continued fraction representation of e. By applying the continued fraction of Gauss, a useful expansion valid for every complex number z can be obtained: .
A similar argument can be made to derive continued fraction expansions for the Fresnel integralsfor the Dawson functionand for the incomplete gamma function.
Complex Continued Fractions and The Gaussian Integers
A simpler version of the argument yields two useful continued fraction expansions of the exponential function. The corresponding series. Variations of this argument can be used to produce continued fraction expansions for the natural logarithmthe arcsin functionand the generalized binomial series.
From Wikipedia, the free encyclopedia. Redirected from Gauss continued fraction. GaussWerkevol. Riemann"Sullo svolgimento del quoziente di due serie ipergeometriche in frazione continua infinita" in Werke.One of interesting ideas of this method is that any number can be represented by a point on the real line and that falls between two integers.
Several attempts have been made during the last years to develop continued fraction algorithm for complex numbers; such algorithm having properties that are known to possess on the regular continued fraction algorithm in the real numbers case.
In the real case, for example, let be any real number, and if is an integer, then. There is one and only one such integer for any given real.
The integer is sometimes called the floor of. For example :. For any real withthere is a unique decomposition where is an integer and is in the unit interval. So, if and only if is an integer.
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The process of finding the continued fraction expansion of a real number is a recursive process that procedes one step at a time. Given any real numberafter steps, the process goes like this one :. Which has integers and real numbers that are members of the unit interval with all positive. We can write another representation :. Ifthe process ends after steps. Otherwise, the process continues at least one more step with. In this way one associates with any real number a sequence, which could be either finite or infinite, of integers.
This sequence is called the continued fraction expansion of real number. For example, can be represented as a continued fraction. Continued fractions have become more common in various other areas since the beginning of the twentieth century. For example, Robert M. Corless  examines the connection between theory of chaotic dynamical systems and continued fractions.
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It only takes a minute to sign up. I have trouble understanding the proof of ergodicity found in the article A continued fraction titbit by M. He then says that an invariant subset should be a member of both and that this implies that it or its complement has zero measure which gives ergodicity.
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Help understanding a geometric proof of the ergodicity of the Gauss measure for continued fractions Ask Question. Asked 6 years, 3 months ago. Active 6 years, 3 months ago. Viewed times. Ben Grossmann k 10 10 gold badges silver badges bronze badges. Active Oldest Votes. Sign up or log in Sign up using Google. Sign up using Facebook. Sign up using Email and Password. Post as a guest Name. Email Required, but never shown. Featured on Meta.